SOLUTION: Jeremy paid for his breakfast with 36 coins consisting of nickels and dimes. If the bill was$3.50 then how many of each type of coin did he use

Question 977702: Jeremy paid for his breakfast with 36 coins consisting of nickels and dimes. If the bill was$3.50 then how many of each type of coin did he use

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
x+y=36,
0.05*x+0.1*y=3.50
x=36-y
Substitute for x
0.05*(36-y)+0.1*y=3.5
Multiply out
1.8-0.05*y+0.1*y=3.5
Combine like terms.
0.05*y=1.7
Isolate y
y=34 dimes
x=36-y
Calculate x
x=2 nickels
Check
0.05*2+0.10*34=3.50
0.10+3.40=3.50
3.5=3.5
codeint1

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