SOLUTION: There were 3000 people at a football game.some paid $10.00 for their tickets other paid $5.00 the total receipts amounted to #25,00. How many tickets of each kind were sold ?
Algebra.Com
Question 965796: There were 3000 people at a football game.some paid $10.00 for their tickets other paid $5.00 the total receipts amounted to #25,00. How many tickets of each kind were sold ?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
10T+5F=25,000
T+F=3,000
T=3,000-F
10(3,000-F)+5F=25,000
30,000-10F+5F=25,000
-5F=25,000-30,000
-5F=-5,000
F=-5,000/-5
F=1,000 FIVE DOLLAR TICKETS WERE SOLD
T+1000=3,000
T=3,000-1,000
T=2,000 TEN DOLLAR TICKETS WERE SOLD.
PROOF:
10*2,000+5*1,000=25,000
20,000+5,000=25,000
25,000=25,000
RELATED QUESTIONS
there were 16 000 people at a hockey game. for tickets some paid $10 & other paid $4. The (answered by Theo,ikleyn,greenestamps)
A concert is attended by 300 people. Some paid ₵6.00 and the rest paid ₵5.00. the... (answered by ikleyn,greenestamps,josgarithmetic)
The gate receipts at the opening state university football game were $133,372. A total of (answered by stanbon)
There were 1500 people at a high school football game. Student tickets were $2.00 and... (answered by doukungfoo)
There were 1500 people at a high school football game. Student tickets were $2.00 and... (answered by elima)
There were 34,000 people at a ball game in Los Angeles. The day's receipts were... (answered by stanbon)
There were 34,000 people at a ball game in Los Angeles. The day's receipts were... (answered by checkley77)
"there were 39,000 people at a ball game the day's receipts were $276,000 how many people (answered by mananth)
There were 41,000 people at a ball game in Los Angeles. THE day's receipts were $340,000. (answered by stanbon)