SOLUTION: If distance ‘s’ is a function of time ‘t’ given by s = t3 – 6t2 – 15t + 12 then the velocity when acceleration is 0 is
Algebra.Com
Question 962807: If distance ‘s’ is a function of time ‘t’ given by s = t3 – 6t2 – 15t + 12 then the velocity when acceleration is 0 is
Answer by amarjeeth123(569) (Show Source): You can put this solution on YOUR website!
s = t3 – 6t2 – 15t + 12
Velocity v=ds/dt=3t2-12t-15
Acceleration=dv/dt=6t-12
When acceleration is zero we have 6t-12=0
t=2 sec
Velocity v=3(2)^2-12(2)-15=12-24-15=-27 units
RELATED QUESTIONS
The position function a particle is given by s(t)= 3t^2 -t^3,t ≥0
When does the... (answered by solver91311)
If s = t2 – t3, find the velocity when the acceleration is... (answered by Alan3354)
The acceleration of a car is given by a=6t and the velocity is 2 when t=0 and the... (answered by ikleyn)
A particle P travels in a straight line and its distance, s metres, from a fixed point O, (answered by Solver92311)
A rocket of mass m = 500 kg is travelling in a straight line for a short time.
The... (answered by Alan3354)
A particle travelling in a straight line passes a fixed point O with a velocity of 1... (answered by mananth)
The acceleration of a point is given by a=4−t^2 m/s^2. Write an equation for the... (answered by Fombitz)
The formula that describes an object’s motion is given by S=ut+12at2
S
=
u
t
+
1
(answered by Boreal,ikleyn)
The height, h (in feet), of a falling object on Mars is given by h=-6t2+s , where t is... (answered by josmiceli)