SOLUTION: 1. A man is q years old while his son is p years old. The sum of their ages is equal to twice the difference of their ages. The product of their ages is 675. Write down the equatio
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Question 959311: 1. A man is q years old while his son is p years old. The sum of their ages is equal to twice the difference of their ages. The product of their ages is 675. Write down the equations connecting their ages and solve the equations in order to find the ages of the man and his son.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
1. A man is q years old while his son is p years old. The sum of their ages is equal to twice the difference of their ages. The product of their ages is 675. Write down the equations connecting their ages and solve the equations in order to find the ages of the man and his son.
***
q=man's age
p=son's age
q+p=2(q-p)
q+p=2q-2p
q=3p
..
q*p=675
q=675/p
..
675/p=3p
3p^2=675
p^2=225
p=√225=15
q=675/15=45
man's age=45
son's age=15
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