SOLUTION: At Ben Again's restaurant, one table ordered three burgers and two orders of fries for $9.00. Another table had two burgers and four orders of fries. Their order cost $10.00. How m

Question 947865: At Ben Again's restaurant, one table ordered three burgers and two orders of fries for $9.00. Another table had two burgers and four orders of fries. Their order cost $10.00. How much did each item sell for?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
At Ben Again's restaurant, one table ordered three burgers and two orders of fries for $9.00. Another table had two burgers and four orders of fries. Their order cost $10.00. How much did each item sell for?
***
let x=price of burgers
let y=price of fries
..
3x+2y=9
2x+4y=10
..
6x+4y=18 (mult. eq. by2)
2x+4y=10
subtract:
4x=8
x=2
2y=9-3x
2y=3
y=3/2=1.5
price of burgers=$2.00 each
price of fries=$1.50 each
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