SOLUTION: ONE number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 405, find the numbers.

Question 941110: ONE number is 3 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 405, find the numbers.
Answer by laoman(51) (Show Source): You can put this solution on YOUR website!
Let the ONE no. be y, the first no. be x and the third no. z
From the statement
y = 3 * x ----eqn1
z = x + 100 -----eqn 2
x + y + z = 405 -----eqn3
let's rearrange the eqns and sole the 3 simultaneous eqns.
3*x - y = 0
x - z = -100
x+y+z = 405
all the best

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