SOLUTION: The sum of two numbers is 80 and the greater number exceeds twice the smaller by 11. find the numbers.
Algebra.Com
Question 935244: The sum of two numbers is 80 and the greater number exceeds twice the smaller by 11. find the numbers.
Found 2 solutions by KlambinRonsentaswer, Alan3354:
Answer by KlambinRonsentaswer(36) (Show Source): You can put this solution on YOUR website!
The answer is 23 and 57 .
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
S + M = 80
M = 2S + 11
RELATED QUESTIONS
The sum of two numbers is 80 and the greatest number exceeds twice the smaller by 11.... (answered by rfadrogane)
the sum of two numbers is 90 and the greater number exceeds twice the smaller by 15. find (answered by Alan3354)
sum of two numbers is 58. the greater number exceeds twice the smaller number by 1. find... (answered by TimothyLamb)
The sum of two numbers is90 and the greater number exceeds twice the smaller by 15.find... (answered by fractalier)
the sum of two numbers is 62, the greater number exceeds twice the smaller number by 5.... (answered by lynnlo)
Find two numbers where three times the smaller number exceeds the larger by 5 and the sum (answered by addingup)
the greater of two numbers is one more than twice the smaller. three times the greater... (answered by jorel1380)
The greater of two numbers is 1 more than twice the smaller. Three times the greater... (answered by edjones)
the greater of two numbers is one more than twice the smaller. three times the greater... (answered by edjones,checkley77)