SOLUTION: Please help me solve this, all help is appreciated!! Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the

Question 924921: Please help me solve this, all help is appreciated!!
Five times the sum of the digits of a two-digit number is 13 less than the original number. If you reverse the digits in the two-digit number, four times the sum of its two digits is 21 less than the reversed two-digit number.
The difference of the original two-digit number and the number with reversed digits is ______.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
5(t + u) = 10t + u -13
5t + 5u = 10t + u - 13
4u =
.......
4(t+ u) = 10u + t -21
4t + 4u = 10u + t -21
4t + (5t-13) = 10(5t-13)/4 + t - 21
9t - 13 = 10(5t-13)/4 + t - 21
36t - 52 = 50t - 130 + 4t -84
162 = 18t
= t and u =
And...checking ... Original Number of 98
5(17) = 98 - 13 = 85
.........
The difference of the original two-digit number and the number with reversed digits ...
98 - 89 = 9

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