SOLUTION: The height of a projectile fired upward from the ground with a velocity of 128 feet per second is given the formula h=-16t^2+128t
A)when will the projectile be 256 feet above gr
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Question 922035: The height of a projectile fired upward from the ground with a velocity of 128 feet per second is given the formula h=-16t^2+128t
A)when will the projectile be 256 feet above ground?
B)will the projectile ever be 300 feet above ground? Explain.
C)when will the projectile be 240 feet above the ground?
D)In how many seconds will the projectile hit the ground?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
The height of a projectile fired upward from the ground with a velocity of 128 feet per second is given the formula h=-16t^2+128t
A)when will the projectile be 256 feet above ground?
h=-16t^2+128t = 256
Solve for t
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B)will the projectile ever be 300 feet above ground? Explain.
Find the vertex of the parabola, that's the max height.
==================
C)when will the projectile be 240 feet above the ground?
h=-16t^2+128t = 240
Solve for t
==================
D)In how many seconds will the projectile hit the ground?
h=-16t^2+128t = 0
Solve for t
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