SOLUTION: A bus leaves a station at 1pm traveling west at an average speed of 44 mi/h. One hour later another bus leaves the same station traveling east at a rate of 48 mi/h. At what time wi

Question 91885This question is from textbook Beginning Algebra
: A bus leaves a station at 1pm traveling west at an average speed of 44 mi/h. One hour later another bus leaves the same station traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart? This question is from textbook Beginning Algebra

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A bus leaves a station at 1 pm traveling west at an average speed of 44 mi/h. One hour later another bus leaves the same station traveling east at a rate of 48 mi/h. At what time will the two buses be 274 mi apart?
:
Let x = traveling time (in hrs) of the 1st bus, when they are 274 mi apart
Then
(x-1) = traveling time of the 2nd bus, when they are 274 mi apart
:
Dist = speed * time
:
1st bus dist + 2nd bus dist = 274 mi
44x + 48(x-1) = 274
44x + 48x - 48 = 274
44x + 48x = 274 + 48
92x = 322
x = 322/92
x = 3.5 hrs, which would make it 4:30 PM, when they are 274 mi apart.
:
Check
44(3.5) + 48(2.5) =
154 + 120 = 274 as given
:
Did this make sense to you? Any questions?
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