You can
put this solution on YOUR website!You can use the formula:

where d = distance, r = rate(speed) and t = time of travel.
For the outbound trip:

hrs, so you can write:

For the return trip, the rate was 5 mph faster than for the outbound trip, so

and

, so you can write:

But the distance out is the same as the distance back, so...

or...

Simplify and solve for

mph This is the outbound speed.

mph This is the return speed.