We begin with Pedro having P peson and Juan having J pesos.

Juan now has J-10 and Pedro has P+10 

     P+10 = 3(J-10)
     P+10 = 3J-30
(1)     P = 3J-40

We begin again with Pedro having P peson and Juan having J pesos.

Pedro has P-10 and Juan has J+10

     J+10 = 2(P-10)
     J+10 = 2P-20
(2)     J = 2P-30

Solve (1) and (2)

        P = 3J-40
        P = 3(2P-30)-40
        P = 6P-90-40
        P = 6P-130
      -5P = -130
        P = 26 pesos

        J = 2P-30
        J = 2(26)-30
        J = 52-30  
        J = 22 pesos

Checking:

We begin with Pedro having 26 peson and Juan having 22 pesos.


Juan gives Pedro 10 pesos. 

Juan now has 22-10=12 and Pedro has 26+10=36 


Pedro will have three times as much money as Juan. 

That checks, since 36 is 3 times 12



Pedro gives Juan 10 pesos, 

Pedro has 26-10=16 and Juan has 22+10=32


Juan will have twice as much money as Pedro.

That checks, since 32 is 2 times 16

Edwin
 

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