SOLUTION: Solve using system of equations (elimination method) show all work

Question 88741: Solve using system of equations (elimination method) show all work
Answer by malakumar_kos@yahoo.com(315) (Show Source): You can put this solution on YOUR website!

Three oranges cost half of what nine apples cost. If one orange and one apple together cost 30 cents, how much does one orange cost?
Let the cost of 1 orange be = X cents and the cost of apple be = Y cents
total cost of 1 orange &1 apple = X+Y = 30 cents........eq'n (1)
given cost of 3 oranges = 1/2(cost of 9 apples)
i.e, 3X = 1/2(9Y)
X = 9Y/6 = 3Y/2
eliminate X in eq'n (1) by substituting for X

therefore X+Y = 30, or 3Y/2+y = 30
3Y+2Y/2 = 30
5Y/2 = 30
Y = 30*2/5 = 12
The cost of an apple = 12 cents
Therefore the cost of an orange = 30-12 = 18 cents

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