SOLUTION: The sum of two numbers is 48. The difference between three times the smaller number and the larger number is 16. Find the numbers.

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Question 87555: The sum of two numbers is 48. The difference between three times the smaller number and the larger number is 16. Find the numbers.
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
X+Y=48 X=48-Y
X-3Y=16
(48-Y)-3Y=16
48-Y-3Y=16
-4Y=16-48
-4Y=-32
Y=-32/-4
Y=8 ANSWER
X+8=48
X=48-8
X=40 ANSWER
PROOF
40-3*8=16
40-24=16
16=16