SOLUTION: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 444 feet, find the width and the length.

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 444 feet, find the width and the length.      Log On


   



Question 855659: The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 444 feet, find the width and the length.
Answer by ramkikk66(644) About Me  (Show Source):
You can put this solution on YOUR website!
The length of a rectangle is 3 feet less than twice the width of the rectangle. If the perimeter of the rectangle is 444 feet, find the width and the length.

Let the width of rectangle be x
Length = 2*x - 3

Perimeter = 2*(Length + Width) = 2*(2*x - 3 + x) = 2*(3*x - 3)
= 6*x - 6 = 444 (given)
6%2Ax+=+450
x+=+75
Length = 2*75 - 3 = 147

Width is highlight%2875%29 ft and length is highlight%28147%29 ft.

Hope you got it :)