SOLUTION: find three consecutive odd positive integers such that the sum of all three is 26 less than the product of the first and second integers. What is the formula to set this up?

Question 852806: find three consecutive odd positive integers such that the sum of all three is 26 less than the product of the first and second integers. What is the formula to set this up?
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find three consecutive odd positive integers such that the sum of all three is 26 less than the product of the first and second integers. What is the formula to set this up?
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1st: 2x-1
2nd: 2x+1
3rd: 2x+3
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Equation:
6x+3 < 4x^2-1-26
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4x^2 - 30 > 0
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x^2 > 15/2
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x > (sqrt(30))/2
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OR
x > (sqrt(30))/2
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Cheers,
Stan H.
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Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find three consecutive odd positive integers such that the sum of all three is 26 less than the product of the first and second integers.
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n-2 + n + n+2 = (n-2)*n - 26
3n = n^2 -2n - 26
n^2 - 5n - 26 = 0
No integer solution.
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