SOLUTION: HI! so this is the question i've been meaning to ask: 1. One leg of a right triangle is twice its other leg. If the length of the shorter leg is x, express the area of the trian

Question 847196: HI! so this is the question i've been meaning to ask:
1. One leg of a right triangle is twice its other leg. If the length of the shorter leg is x, express the area of the triangle as a function of x. What is the domain of this function?
Im really confused since there are only 2 givens and well, a triangle has 3 sides, but I'm also thinking maybe Special Right Triangles have to be used. Maybe the triangle is 30 and 60 degrees in the inside and that the hypotenuse is 2x, the opposite is x square root of 3, and adjacent is x.
Answer by swincher4391(1107) (Show Source): You can put this solution on YOUR website!
Good idea, but if that was the case then we'd have that the other leg would be sqrt(3)*x and not 2x. Notice that given two legs, we have the height and the base [it does not matter which is which]. So our area = 1/2 * b *h = 1/2 * x * 2x = x^2.
Domain: Now remember what x represents. It represents a distance. So our domain is all positive values of x. Or x>0.
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