SOLUTION: An automobile radiator contains 16 L of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should be drained and replaced with pure antifreeze so that t
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Question 842207: An automobile radiator contains 16 L of antifreeze and water. This mixture is 30% antifreeze. How much of this mixture should be drained and replaced with pure antifreeze so that the mixture will be 50% antifreeze?
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
liters of
antifreeze in radiator initially
-------------------------
Let = liters of mixture to be
removed and replaced with pure antifreeze
---------------------------------------
= liters of pure antifreeze removed
-----------------------------------------
In words:
( liters of antifreeze you end up with ) / ( liters of mixture you end up with ) = 50%
liters should be drained
and replaced with pure antifreeze
------------------------------------
check answer:
liters of antifreeze removed
There is now liters
of antifreeze in radiator
liters of antifreeze is put back in
There is now liters of
antifreeze in radiator and total of liters
= 50%
OK
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