SOLUTION: Dmitri needs 9 liters of a 57% solution of sulfuric acid for a research project in molecular biology. He has two supplies of sulfuric acid solution: one is an unlimited supply of t
Algebra.Com
Question 839533: Dmitri needs 9 liters of a 57% solution of sulfuric acid for a research project in molecular biology. He has two supplies of sulfuric acid solution: one is an unlimited supply of the 72% solution and the other an unlimited supply of the 45% solution. How many liters of each solution should Dmitri use?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Do it like this one. Only the numbers are different.
-----------
Amanda wants to make 8 gal. of a 20% saline solution by mixing together a 56% saline solution and a 8% saline solution. How much of each solution must she use?
================
e = amount of 8%
f = amount of 56%
---
e+ f = 8 (total solution)
8e + 56f = 20*8 (total saline)
---
e+ f = 8
e + 7f = 20
------------ Subtract
-6f = -12
f = 2
e = 6
RELATED QUESTIONS
Dmitri needs 7 liters of a 24% solution of sulfuric acid for a research project in... (answered by josmiceli)
Through(3,4) perpendicular to y =-3x+2
Dmitri needs 5 liters of a 43% solution of... (answered by ewatrrr)
Dmitri needs 7 liters of a 24% solution of sulfuric acid for a research project in... (answered by dragonwalker)
Dmitri needs 5 liters of a 43% solution of sulfuric acid for a research project in... (answered by CharlesG2,ewatrrr)
can you show me how to do this step by step so i can use this as notes for future... (answered by josgarithmetic)
Dmitri needs 7 liters of a 36% solution of sulfuric acid for a research project in... (answered by richwmiller)
1- Arielle needs 9 liters of a 65% solution of sulfuric acid for a research project... (answered by lwsshak3)
A chemist has two solutions of sulfuric acid. The first is one half sulfuric acid and... (answered by ankor@dixie-net.com)
A chemist of needs a 50% solution sulfuric acid having a volume of 72 liters. how much... (answered by stanbon)