SOLUTION: The hight of an object moving vertically is given by s= -16t^2+60t+112 where s is measured in feet and t is measured in seconds.
Find the objects velocity when t=0
find its m
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Question 826570: The hight of an object moving vertically is given by s= -16t^2+60t+112 where s is measured in feet and t is measured in seconds.
Find the objects velocity when t=0
find its maximum hight and when it occurs
Find the velocity when s=0
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The height of an object moving vertically is given by
s(t) = -16t^2+60t+112 where s is measured in feet and t is measured in seconds.
Find the objects velocity when t=0
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Velocity at time = t is the derivative of "s":
s'(t) = -32t+60
s'(0) = 60 ft/sec
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find its maximum hight and when it occurs
Max height occurs when t = -b/(2a) = -60/(-32) = 1.875 sec
s(1.875) = 168.25 ft.
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Find the velocity when s=0
When s = 0 the object will be on the groud.
Its velocity will be zero.
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Cheers,
Stan H.
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