SOLUTION: the line containing H(2,2) and parallel to the graph of y=x-3 m= ? (1?) point slope form= ? slope intercept form= ? Standard Form= ? (x-y=3)

Question 825606: the line containing H(2,2) and parallel to the graph of y=x-3
m= ? (1?)
point slope form= ?
slope intercept form= ?
Standard Form= ? (x-y=3)

Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
If parallel, then slope is the same as the given line. m=1 for both lines when expressed in slope-intercept form, y=mx+b.

The line containing H(2,2) is y=x+b, and we find by through substituting the given point which is on y=x+b.
'
b=y-x
b=2-2
b=0
The sought line intersects the origin.
The line in slope-intercept form is simply

The point-slope form comes from using definition of slope.

and the rest follows... but this form does not give you any great advantage, since for such line, you could say y-12=x-12, or any .

You can find the standard form equation on your own.
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