SOLUTION: Allied Airlines charges $90 for a ticket to fly between two cities 260 mi apart abd $150 for a ticket to fly between two cities 500 mi apart. At this rate, what would it cost for a

Question 82480: Allied Airlines charges $90 for a ticket to fly between two cities 260 mi apart abd $150 for a ticket to fly between two cities 500 mi apart. At this rate, what would it cost for a trip between two cities 1000 mi apart?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Allied Airlines charges $90 for a ticket to fly between two cities 260 mi apart abd $150 for a ticket to fly between two cities 500 mi apart. At this rate, what would it cost for a trip between two cities 1000 mi apart?
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You have two points (260,90) and (500,150)
slope = [150-90]/[500-260] = 60/240 = 1/4
You want an equation of the form cost=m(distance)+b where cost is 90 when
distance is 260 and m=1/4; solve for "b":
90 = (1/4)260+b
90 = 65+b
b=25
EQUATION: Cost = (1/4)(distance)+25
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Cost when distance = 1000 mi:
cost = (1/4)(1000)=25
cost = 250+25
cost = $275
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Cheers,
Stan H.
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