SOLUTION: If a,b,c are real numbers such that a^2+2b=7, b^2+4c=-7, c^2+6a=-14, then the value of a^2+b^2+c^2 is equal to: (A) 14 (B) 21 (C) 28 (D) 35 This query was already on your websit

SOLUTION: If a,b,c are real numbers such that a^2+2b=7, b^2+4c=-7, c^2+6a=-14, then the value of a^2+b^2+c^2 is equal to: (A) 14 (B) 21 (C) 28 (D) 35 This query was already on your websit

Algebra.Com

Question 810515: If a,b,c are real numbers such that a^2+2b=7, b^2+4c=-7, c^2+6a=-14, then the value of a^2+b^2+c^2 is equal to:
(A) 14 (B) 21 (C) 28 (D) 35
This query was already on your website. I have made a few changes though!
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
a = -3, b = -1, c = -2,
a^2+b^2+c^2 = 14
(A) 14
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