SOLUTION: Brad has a collection of dimes and quarters totaling $47.50. The number of quarters is 10 more than twice the number of dimes. How many coins of each kind does he have?

Question 810384: Brad has a collection of dimes and quarters totaling $47.50. The number of quarters is 10 more than twice the number of dimes. How many coins of each kind does he have?
Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
10d + 25q = 4750
q = 2d + 10
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10d + 25q = 4750
10d + 25(2d + 10) = 4750
10d + 50d + 250 = 4750
60d = 4500
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d = 75
q = 2(75) + 10 = 160
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