SOLUTION: A jet takes 9 hours to travel a distance of 7776 miles against the wind. The return trip takes 8 hours with the wind. What is the rate of the jet in still air and what is the rate

Question 806342: A jet takes 9 hours to travel a distance of 7776 miles against the wind. The return trip takes 8 hours with the wind. What is the rate of the jet in still air and what is the rate of the wind?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A jet takes 9 hours to travel a distance of 7776 miles against the wind. The return trip takes 8 hours with the wind. What is the rate of the jet in still air and what is the rate of the wind?
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rate with the wind: 7776/8 = 972 mph
rate against the wind: 7776/9 = 964 mph
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Equation:
p + w = 972
p - w = 864
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Add and solve for "p"::
2p = 1836
plane = 918 mph (speed of the plane in still air)
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Solve for "w":
p+ w = 972
918 + w = 972
w = 54 mph (speed of the wind)
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Cheers,
Stan H.
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