SOLUTION: Water gets sprayed out of a water gun and follows a parabolic path described by h=-4.9t^2+8t+1.5 What is the maximum height of the water and when is it reached?

Question 797050: Water gets sprayed out of a water gun and follows a parabolic path described by
h=-4.9t^2+8t+1.5 What is the maximum height of the water and when is it reached?
Found 2 solutions by stanbon, josmiceli:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Water gets sprayed out of a water gun and follows a parabolic path described by
h=-4.9t^2+8t+1.5 What is the maximum height of the water and when is it reached?
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Max occurs when t = -b/(2a) = -8/(2*-4.9) = 0.8163 seconds
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Max height = h(0.8163) = 4.7653 meters
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Cheers,
Stan H.

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

If the form of the equation is
, then the x-coordinate of
the maximum or minimum is at
In your problem,

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Now find

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Here's the plot:

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