SOLUTION: a man left place A at 6:00 am expecting to reach place B at 9:00 am. but after walking one hour, he was delayed for half an hour, and so he had to increase his rate 1 mile per hour

Question 775661: a man left place A at 6:00 am expecting to reach place B at 9:00 am. but after walking one hour, he was delayed for half an hour, and so he had to increase his rate 1 mile per hour to reach place B at 9:00 am. find his speed before the delay and the distance between place A and place B.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
a man left place A at 6:00 am expecting to reach place B at 9:00 am.
but after walking one hour, he was delayed for half an hour, and so he had to increase his rate 1 mile per hour to reach place B at 9:00 am.
find his speed before the delay and the distance between place A and place B.
:
let s = his normal walking speed
then
(s+1) = his faster walking speed
:
dist = 3s
Because of the delay, actual walking time only 2.5 hrs
:
dist at normal speed + dist at faster speed = total dist
1s + 1.5(s+1) = 3s
s + 1.5s + 1.5 = 3s
2.5s + 1.5 = 3s
1.5 = 3s - 2.5s
1.5 = .5s
s = 1.5 /.5
s = 3 mph is his normal walking speed
then
3(3) = 9 mi is the distance
:
:
Check
3 + 1.5(4) = 9
3 + 6 = 9
RELATED QUESTIONS
A man left A at 6:00 am expecting to reach B at 9:00 am. But after walking one hour, he... (answered by josgarithmetic)

. A man left A at 6:00 a.m. expecting to reach B at 9:00 a.m. But after walking one... (answered by ankor@dixie-net.com)

a motorist travelling at constant speed leaves A at 11 00 intending to arrive B , 100km... (answered by josmiceli,MathTherapy)

A salesman started walking from office A at 8:30 AM. at the rate of 2.50 kph. He arrived... (answered by ankor@dixie-net.com,ikleyn)

A movers van left Middletown at 8:00 am and drove to bayside at an average speed of 70... (answered by checkley79,josmiceli)

The Puzzle Sara really needed to go to the doctor for her check-up... and to her... (answered by richwmiller)

a man left his house at 7:00 AM and traveled at an average aped of 60kph. He arrived at... (answered by josgarithmetic)

Please help. SAT Problems: For what values of p does the equation px = 10 have a... (answered by greenestamps)

SAT Problems: For what values of p does the equation px = 10 have a solution −5; 1;... (answered by greenestamps)