SOLUTION: One number is 1 less than a second number. Twice the second number is 20 less than 4 times the first. Find the two numbers? I can never figure out how to set these equations up,

Question 763755: One number is 1 less than a second number. Twice the second number is
20 less than 4 times the first. Find the two numbers? I can never figure out how to set these equations up, could you show me the proper steps. Thank you very much.
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!

One number is 1 less than a second number. Twice the second number is
20 less than 4 times the first. Find the two numbers? I can never figure out how to set these equations up, could you show me the proper steps. Thank you very much.

Let the smaller, or first number be S

Then larger or second number = S + 1

Therefore, 2(S + 1) = 4S - 20

2S + 2 = 4S - 20

2S - 4S = - 20 - 2

- 2S = - 22

S, or smaller/first number = , or

Larger/second number = S + 1, or

You can do the check!!

Further help is available, online or in-person, for a fee, obviously. Send comments, �thank-yous,� and inquiries to �D� at MathMadEzy@aol.com
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