SOLUTION: I have been trying to turn this word problem into a linear equation for a week now with no success. Can you help? A downtown employee is looking for the best option for parki

Question 752091: I have been trying to turn this word problem into a linear equation for a week now with no success. Can you help?
A downtown employee is looking for the best option for parking a car during a 5 day work week. Garage A offers unlimited parking at a flat rate $150.00 per month. Garage B offers an hourly rate of $5.00 for parking. Which option is best for the employee on a monthly basis?
The employee is parking 160 hours per month. This is a word problem that I had to come up with on my own make 2 linear equations out of it and then graph it and show where they intercept.
Any help would be appreciated. Thank you!
Found 2 solutions by MathTherapy, john7896:
Answer by MathTherapy(10555) (Show Source): You can put this solution on YOUR website!
I have been trying to turn this word problem into a linear equation for a week now with no success. Can you help?
A downtown employee is looking for the best option for parking a car during a 5 day work week. Garage A offers unlimited parking at a flat rate $150.00 per month. Garage B offers an hourly rate of $5.00 for parking. Which option is best for the employee on a monthly basis?
The employee is parking 160 hours per month. This is a word problem that I had to come up with on my own make 2 linear equations out of it and then graph it and show where they intercept.
Any help would be appreciated. Thank you!

Garage A's charge is $150

Garage B's charge = 5H, with H being amount of hours of parking

5H < 150

H, or hours that'll make garage B's cost less than garage A's should be < , or <

This means that if a person needs to park for less than 30 hours per month, then garage B will be cheaper.

At 30 hours per month both costs are equal.

Parking for 160 hours DEFINITELY makes garage A the cheaper of the two. You can do the math to see why this is so.

You can graph garage A's linear equation as A(x) = 0x + 150, with x being the amount of monthly-hours of parking

Garage B's equation: B(x) = 5x, with x being the amount of hours of monthly-hours of parking.

You'll then see where the two equations intersect, which is the point where the two costs are equal.
Answer by john7896(1) (Show Source): You can put this solution on YOUR website!
The above answer to the question is incorrect because
While some substitution steps appear in the submission, an algebraic solution needs to be provided that shows the solution of the system.
While parts of the graph appear accurate, the graph of the second option equation is not accurate. Parts of the graph of equation one appear only as a sequence of unconnected points. The graph of the first equation should also not connect to the origin. Revision is needed.
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