SOLUTION: 12 boys and 8 men can finish a piece of work in 5 days.and 8 boys nd 6men can finish it in 7 days . find the time by 1 man alone and 1 boy alone to finish the work.

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Question 743397: 12 boys and 8 men can finish a piece of work in 5 days.and 8 boys nd 6men can finish it in 7 days . find the time by 1 man alone and 1 boy alone to finish the work.

Answer by Edwin McCravy(20055)   (Show Source): You can put this solution on YOUR website!
12 boys and 8 men can finish a piece of work in 5 days.and 8 boys nd 6men can finish it in 7 days . find the time by 1 man alone and 1 boy alone to finish the work.
Suppose 1 boy alone can can do 1 job in b days.

Then 1 boy's work rate is 1 job per b days or  or 

Then 12 boys' work rate is 12 times  or 

and 8 boys' work rate is 8 times  or 

Suppose 1 man alone can can do 1 job in m days.

Then 1 man's work rate is 1 job per m days or  or 

Then 8 men's work rate is 8 times  or 

and 6 men's work rate is 6 times  or 

>>12 boys and 8 men can finish a piece of work in 5 days<<
So the combined work rate of 12 boys and 8 men is 1 job per 5 days or  or 

So we get one equation from




>>8 boys and 6 men can finish it in 7 days<<

So the combined work rate of 8 boys and 6 men is 1 job per 7 days or or
So we get the other equation from


So we have the system of equations

IMPORTANT: DO NOT CLEAR OF FRACTIONS:
To eliminate the terms in m, multiply the first equation
through by 3, and multiply the second equation through
by -4:


Adding those equations term by term gives

NOW we can clear of fractions. Multiply both sides
by the LCD of 35b


So each boy will take 140 days.
Substitute 140 for b in



Multiply both sides by 10m


So each man will take 80 days.
Edwin

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