SOLUTION: Elimination/solving linear equations One airplane costs four times as much as a certain car. Two such planes cost 6000 more than six of the cars. Find the cost of each

Question 743227: Elimination/solving linear equations
One airplane costs four times as much as a certain car. Two such planes cost 6000 more than six of the cars. Find the cost of each
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
One airplane costs four times as much as a certain car. Two such planes cost 6000 more than six of the cars. Find the cost of each
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Equations:
a = 4b
2a = 6b + 6000
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a = 4b
a = 3b + 3000
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4b = 3b + 3000
b = $3000 (cost of one of the cars)
a = 4b = $12,000 (cost of one of the airplanes)
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Cheers,
Stan H.
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