You can
put this solution on YOUR website!A small company produces both standard (let # be x) and deluxe (let # be y) playhouses.
-------------
The standard playhouses take 12 hours of labor to produce, and the deluxe playhouses take 20 hours.
The labor available is limited to 800 hours per week,
Labor Inequality: 12x + 20y <=800
--------------
and the total production capacity is 50 items per week.
Capacity Inequality: x + y <=50
---------------
Existing orders require the company to produce at least 10 standard playhouses and 15 deluxe playhouses per week.
x >= 10
y >= 15
-------------
Write a system of inequalities representing this situation, where x is the number of standard playhouses and y is the number of deluxe playhouses.
------------
Then graph the system of inequalities.
Solve the inequalities for y:
Labor Inequality y <= (-3/5)x+40
Capacity Inequl y <= -x+50
Note: x >= 10 tells you the Domain for the solution set.
y >=15 tells you the Range for the solution set.
------------
Graph the EQUALITIES: y=(-3/5)x+40; y=-x+50 to determine the boundaries of the solution set.
The solution is the intersection of the inequality and equality sets
=============
Cheers,
Stan H.
(