SOLUTION: how do you solve; the sum of two numbers is 40. Four times the larger number decreased by 5 equals 11 more than 8 times the smaller number. write two equations to represent the pre

Question 723753: how do you solve; the sum of two numbers is 40. Four times the larger number decreased by 5 equals 11 more than 8 times the smaller number. write two equations to represent the previous sentences
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
let x, y be the numbers x>y
x+y=40.................(1)
4x-5=8y+11
4x-8y=16................(2)
multiply (1) by 8 and add it to (2)
12x= 336
x=28
28 & 12 are the numbers
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