SOLUTION: The perimeter of a rectangle is 32ft. The length is 8 ft. longer than the width find the dimensions. Write a system of linear equations solve the resulting system. Let x be the le
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Question 717953: The perimeter of a rectangle is 32ft. The length is 8 ft. longer than the width find the dimensions. Write a system of linear equations solve the resulting system. Let x be the length and y be the width.
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
The perimeter of a rectangle is 32ft. The length is 8 ft. longer than the width find the dimensions. Write a system of linear equations solve the resulting system. Let x be the length and y be the width.
System:
2(x+y)=32
x = y+8
solution:
2(y+8+y)=32
2(2y+8)=32
2y+8=16
2y = 8
y = 4
x = 12
Answer: legth = 12 width = 4
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