SOLUTION:
2. Two numbers have a difference of 36. The sum of these 2 numbers is 6 times the value of the smaller number. What are the numbers?
Algebra.Com
Question 715771:
2. Two numbers have a difference of 36. The sum of these 2 numbers is 6 times the value of the smaller number. What are the numbers?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
X-Y=36
X=36+Y
X+Y=6Y
(36+Y)+Y=6Y
2Y-6Y=-36
-4Y=-36
Y=-36/-4
Y=9 ANS.
X-9=36
X=36+9
X=45 ANS.
PROOF:
45+9=6*9
54=54
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