SOLUTION: Nathan needs to make 30L of a 28% acid solution. He has 2 bottles, one containing 20% acid and the other containing 50% acid. What volume of each should he mix together to make the

Question 714702: Nathan needs to make 30L of a 28% acid solution. He has 2 bottles, one containing 20% acid and the other containing 50% acid. What volume of each should he mix together to make the 28% acid solution?
Answer by josgarithmetic(39630) (Show Source): You can put this solution on YOUR website!
A very routine exercise. Let x = volume of the 20% acid to use and y = volume of the 50% acid to use.

AND

The numbers were picked to make the arithmetic easier to do.
Managing the percentage equation,
(2x+5y)/3=28 just by removing factor of from left side;
2x+5y=3*28
2x+5y=84

System to solve is this:

Possible next step is

liters for the 50% acid.
You can continue from here...

Also notice, if 30 liters mixture is to result, as described, then this must be some huge bottle containing the x liters of the other acid!
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