SOLUTION: Admission to an amusement park is 8 dollars for adults and 5 dollars for children.if 201 was paid for 33 tickets, how many of each were purchased

Question 707704: Admission to an amusement park is 8 dollars for adults and 5 dollars for children.if 201 was paid for 33 tickets, how many of each were purchased
Found 2 solutions by nerdybill, Stitch:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Admission to an amusement park is 8 dollars for adults and 5 dollars for children.if 201 was paid for 33 tickets, how many of each were purchased
.
Let x = number of adult tickets
then
33-x = number of children tickets
.
8x + 5(33-x) = 201
8x + 165-5x = 201
3x + 165 = 201
3x = 36
x = 12 (adult tickets)
.
Children's tickets:
33-x = 33-12 = 21
Answer by Stitch(470) (Show Source): You can put this solution on YOUR website!
Let A = number of adult tickets
Let C = number of child tickets
Equation 1:
Equation 2:
--------------------------------
Solve equation 2 for one of the variables.
Equation 2:

Plug (33-C) into equation 1 for A
Equation 1:

Multiply the 8 through.

Combine like terms.

Subtract 264 from both sides.

Divide both sides by -3.

Now solve for A, using 21 for C

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