SOLUTION: a merchant purchased a number of coats each at the same price for a total of $7200.he sold them at $400 each,thus realing a profit equal to the cost of 8 coats.calculate the numbe

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: a merchant purchased a number of coats each at the same price for a total of $7200.he sold them at $400 each,thus realing a profit equal to the cost of 8 coats.calculate the numbe      Log On


   



Question 703868: a merchant purchased a number of coats each at the same price for a total of $7200.he sold them at $400
each,thus realing a profit equal to the cost of 8 coats.calculate the number of coats purchased

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
n=number of coats purchased
c=cost of one coat, in $
The cost for n coats, in $, is nc=7200
The cost for 8 coats, in $, is 8c
The n coats were sold for a total of $400n
The profit realized was $400n-7200 and that is equal to $8c, so 400n-7200=8c
The system of equations to solve is
system%28nc=7200%2C400n-7200=8c%29
400n-7200=8c --> 50n-900=c (dividing both sides of the equal sign by 8)
So highlight%28c=50n-900%29
Substituting the expression 50n-900 for c in nc=7200
we get a quadratic equation:
n%2850n-900%29=7200 --> 50n%5E2-900n=7200 --> 50n%5E2-900n-7200=0
Dividing both sides of the equal sign by 50 we simplify that to
n%5E2-18n-144=0 which is easy to solve by factoring,
because we see that n%5E2-18n-144=%28n-24%29%28n%2B6%29
So we can write the equation as %28n-24%29%28n%2B6%29=0
and realize that n=24 and n=-6 are solutions to the equation.
Since the number of coats could not be negative, we discard n=-6 and our solution is highlight%28n=24%29.
The number of coats purchased was highlight%2824%29.
We could even calculate the cost paid for each coat:
Substituting that value in c=50n-900 we find
c=50%2A24-900 --> c=1200-900 --> c=300.

NOTE:
If we cannot see that n%5E2-18n-144=%28n-24%29%28n%2B6%29,
factoring is not an option to solve n%5E2-18n-144=0.
Then, we have to use the quadratic formula that says that the solutions to
ax%5E2%2Bbx%2Bc=0 are given by x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
In the case of n%5E2-18n-144=0 we are using n for x,
a=1, b=-18 and c=-144, so
n+=+%28-%28-18%29+%2B-+sqrt%28+%28-18%29%5E2-4%2A1%2A%28-144%29+%29%29%2F%282%2A1%29+
n+=+%2818+%2B-+sqrt%28+324%2B576+%29%29%2F2+
n+=+%2818+%2B-+sqrt%28900%29%29%2F2+ --> n+=+%2818+%2B-+30%29%2F2+
The solutions are
n=%2818+%2B+30%29%2F2=48%2F2=24 and
n=%2818+-+30%29%2F2=%28-12%29%2F2=-6