SOLUTION: Mary has 2 CDs more than jamil together they have 30 CDs how many CDs does Mary have?

Question 698336: Mary has 2 CDs more than jamil together they have 30 CDs how many CDs does Mary have?
Answer by neatmath(302) (Show Source): You can put this solution on YOUR website!

This is a system of two equations.

Let M be the number of Mary's cds.

Let J be the number of Jamil's cds.

Then we have:

given

given

Let's just substitute the value of M in the first equation into the second equation:

Jamil has 14 cds. It is then easy to see that Mary has 16 cds.

Check it, it works!

I hope this helps! Keep practicing! :)

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