SOLUTION: the digit at the tens place of a two digit number is three times the digit at ones place.if the sum of this number and the formed by reversing its digit is 88, find the number .

Question 673652: the digit at the tens place of a two digit number is three times the digit at ones place.if the sum of this number and the formed by reversing its digit is 88, find the number .

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
let x = the 10's digit
let y = the units
then
10x+y = the number
:
Write an equation for each statement:
:
" the digit at the tens place of a two digit number is three times the digit at ones place."
x = 3y
:
"The sum of this number and the number formed by reversing its digit is 88,"
(10x + y) + (10y + x) = 88
10x + x + 10y + y = 88
11x + 11y = 88
simplify, divide by 11
x + y = 8
:
You should be able to do it now. (Replace x with 3y)

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