SOLUTION: For question #276198. Can someone explain the reasoning as to how this problem was solved. For example, I know that Moulders's distance = Scully's distance, that r*t = r*t. But wh

SOLUTION: For question #276198. Can someone explain the reasoning as to how this problem was solved. For example, I know that Moulders's distance = Scully's distance, that rt = rt. But wh

Question 670253: For question #276198. Can someone explain the reasoning as to how this problem was solved. For example, I know that Moulders's distance = Scully's distance, that r*t = r*t. But why does 1/2 hr get added to Moulder's time? Does this mean he spends more time traveling his distance? (when you go back and plug in the answer 10 5/6 hrs into the equation, it's basically a distance equals distance equation, and this shows that Moulder takes longer to travel his distance. This is what I am basing my questions on.)
Also, how does this fit in with when Scully catches up with Moulder?
Thanks Ralph
Answer by MathTherapy(10553) (Show Source): You can put this solution on YOUR website!

For question #276198. Can someone explain the reasoning as to how this problem was solved. For example, I know that Moulders's distance = Scully's distance, that r*t = r*t. But why does 1/2 hr get added to Moulder's time? Does this mean he spends more time traveling his distance? (when you go back and plug in the answer 10 5/6 hrs into the equation, it's basically a distance equals distance equation, and this shows that Moulder takes longer to travel his distance. This is what I am basing my questions on.)
Also, how does this fit in with when Scully catches up with Moulder?
Thanks Ralph

Let the time taken by Molder to get to the �catch-up� point be T
Then time taken by Scholy to get to the �catch-up� point is T � �hour
Molder is going to take a longer time to get to the �catch-up� point since he�s traveling at a slower speed

When Scoly catches up to Molder, both would�ve traveled the same distance
We therefore form a distance equation�one that says:
Molder�s distance traveled to �catch-up� point = Scholy�s distance traveled to the �catch-up� point, which is algebraically written as:

65T = 68T � 34
65T � 68T = - 34
� 3T = - 34
T, or time it�ll take Molder to get to �catch-up� point = , or hours, or 11 hours, 20 minutes

After leaving at 8:30 AM, and after traveling for 11 hours, 20 minutes to get to �catch-up� point, Molder will reach �catch-up� point at PM.

Yes, Molder does take a longer time to cover the same distance as Scholy since he (Molder) is traveling at a slower rate of speed (65 mph as opposed to Scholy's 68 mph).

Additionally, you can either let Molder's time be T, and subtract 1/2 hour to get Scholy's time, or let Scholy's time be T, and then add 1/2 hour to get Molder's time.

Send comments and �thank-yous� to �D� at MathMadEzy@aol.com
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