SOLUTION: a collection of dimes and quaters is worth $19. there are 91 coins in all. how many of each are there?
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Question 669926: a collection of dimes and quaters is worth $19. there are 91 coins in all. how many of each are there?
Answer by ReadingBoosters(3246) (Show Source): You can put this solution on YOUR website!
x = dimes
y = quarters
...
x+y = 91
.1x + .25y = 19
...
.1(91-y) + .25y = 19
9.1 - .1y + .25y = 19
9.1 + .15y = 19
.15y = 19-9.1
.15y = 9.9
quarters
...
91 - 61 = dimes
...
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