SOLUTION: According to service records for Maya's Volkswagon, the bakes were checked at 42.1 thousand miles and at 88.6 thousand miles. At the first check, there were 4.8 mmm of friction mat

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Question 6665: According to service records for Maya's Volkswagon, the bakes were checked at 42.1 thousand miles and at 88.6 thousand miles. At the first check, there were 4.8 mmm of friction material left on the rear brake pads; at the second check, there were 2.1 mm remaining.
1. Express the data in the form of two ordered pairs, (x,y), where x stands for the distance driven in thousands of miles and y stands for the thickness of the brake pads in mm.

I think the answer is -.058, but when I plug that in to later equations, it doesn't work.
Answer by prince_abubu(198) About Me  (Show Source):
You can put this solution on YOUR website!
At 42.1 thousand miles, there were 4.8 mm of friction material. If you put that in an ordered pair (x,y) where x is the mile mark and y is the amount of friction material, it would be (42.1,4.8). Do that to the other mile mark and the thinner material, you'd get the ordered pair (88.6,2.1).

I'm not sure what else the problem is asking for. Actually, your answer of -0.058 ends being the rate of which the brake pad thickness decreases, which is actually a decrease of 0.058 mm for every 1000 miles.

So, what other equations are you using, then, that this -0.058 mm/1000 mi doesn't work? Keep in mind that whatever the equations may be, the -0.058 is NOT a millimeter mark.