SOLUTION: Mr. Samuel has a 10% solution of hydrochloric acid and a 50% solution of hydrochloric acid. How much of each type must be mixed to obtain 60 liters of a 25% solution of hydrochlori

SOLUTION: Mr. Samuel has a 10% solution of hydrochloric acid and a 50% solution of hydrochloric acid. How much of each type must be mixed to obtain 60 liters of a 25% solution of hydrochlori

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Question 66165: Mr. Samuel has a 10% solution of hydrochloric acid and a 50% solution of hydrochloric acid. How much of each type must be mixed to obtain 60 liters of a 25% solution of hydrochloric acid?
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.5x+.1(60-x)=60*.25
.5x+6-.1x=15
.4x=15-6
.4x=9
x=9/.4
x=22.5 liters of 50% & (60-22.5)=37.5 liters of 10% are needed
proof
.5*22.5+.1(60-22.5)=60*.25
11.25+.1(37.5)=15
11.25+3.75=15
15=15
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