SOLUTION: The tens digit of a two-digit number is 2 less than twice the units digit. The number is 17 times the units digit. Find the number.
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Question 66135: The tens digit of a two-digit number is 2 less than twice the units digit. The number is 17 times the units digit. Find the number.
Found 2 solutions by Nate, stanbon:
Answer by Nate(3500) (Show Source): You can put this solution on YOUR website!
The number is defined as:
10a + b = a.b.
a = 2b - 2
10a + b = 17*b
Plug:
10(2b - 2) + b = 17b
20b - 20 + b = 17b
4b = 20
b = 5
Plug:
a = 2b - 2
a = 10 - 2 = 8
Number: 85
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The tens digit of a two-digit number is 2 less than twice the units digit. The number is 17 times the units digit. Find the number.
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Let the two digit number be 10x+y
x is the ten's digit and y is the units digits.
Equations:
1st: x+2=2y
2nd: 10x+y=17y
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Rewrite the equations as follows:
3rd: x=2y-2
4th: 10x-16y=0
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Substitute 3rd into 4th to get:
10(2y-2)-16y=0
4y=20
y=5
Then x=2(5)-2
x=8
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The number is 10x+y=80+5=85
Cheers,
Stan H.
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