SOLUTION: one number is 4 less than 3 times a second number. If 3 more than twice the first number is decreased by the second, the result is 11. Find both numbers please help me i need

Question 66039:
one number is 4 less than 3 times a second number. If 3 more than twice the first number is decreased by the second, the result is 11. Find both numbers
please help me i need this tonight!
Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
QUESTION:

one number is 4 less than 3 times a second number. If 3 more than twice the first number is decreased by the second, the result is 11. Find both numbers

ANSWER:
Here it is given that one number is 4 less than 3 times a second number.

So lets take the second number as x.

3 times a second number= 3x
4 less than 3 times a second number = 3x - 4

Then we have first number is 4 less than 3 times a second number
That is first number is 3x-4

Now twice the first number = 2(3x-4)

Again 3 more than twice the first number = 2(3x -4)+ 3

Now...3 more than twice the first number is decreased by the second(that is x)
is equal to 11

==> 2(3x -4)+ 3 - x = 11

Remove the parenthesis...

==> 2* 3x - 2*4 + 3 - x = 11

==> 6x - 8 + 3 - x = 11

==> 5x -5 = 11

Add 5 on both sides...

==> 5x - 5 + 5 = 11 + 5

==> 5x = 16

Divide by 5 on both sides...

==> 5x/5 = 16/5

==> x = 16/5

Now substitute this value in 3x-4

==> first number = 3*16/5 - 4

==> 48/5 -4

==> 48/5 -4*5/5

==> (48 - 20)/5

==> 28/5

So the numbers are 16/5 and 28/5

Hope you understood...

Regards..

praseena.

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