SOLUTION: 3boys work on a farm . They decide to weigh themselves, the scale begins at100kg and no boy weighs more than 100kg. They weigh themselves in pairs and found these amounts. Jamal wa
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Question 658445: 3boys work on a farm . They decide to weigh themselves, the scale begins at100kg and no boy weighs more than 100kg. They weigh themselves in pairs and found these amounts. Jamal was sure he weighed the most.
Hector+Simon=132kg
Simon+Jamal=151kg
Jamal+hector =137kg
What did each boy weigh using equations show answer.
I can't figure this out to help my daughter, please help!!
Thank you
Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
3boys work on a farm . They decide to weigh themselves, the scale begins at100kg and no boy weighs more than 100kg. They weigh themselves in pairs and found these amounts. Jamal was sure he weighed the most.
Hector+Simon=132kg
Simon+Jamal=151kg
Jamal+hector =137kg
What did each boy weigh using equations show answer.
I can't figure this out to help my daughter, please help!!
Thank you
Let Hector’s, Simon’s, and Jamal’s weights be H, S, and J, respectively
Then: H + S = 132 ------ eq (i)
S + J = 151 ------ J + S = 151 ------ eq (ii)
J + H = 137 ---- H + J = 137 ----- eq (iii)
H – J = - 19 -------- Subtracting eq (ii) from eq (i) ---- eq (iv)
2H = 118 ------- Adding eqs (iv) & (iii)
H, or Hector’s weight = , or kg
59 + S = 132 ------ Susbstituting 59 for H in eq (i)
S = 132 - 59
S, or Simon’s weight = kg
J + 73 = 151 ----- Substituting 73 for S in eq (ii)
J = 151 – 73
J, or Jamal’s weight = kg
With Jamal at 78 kg, he’s definitely the heaviest of the three.
You can do the check, I'm sure!!!
Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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