SOLUTION: I need help with these problems can you solve these out for me in steps? Set 5 1. factor completely: x to the 2nd power -7x -30 2. factor completely: x to the 2nd power +

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Question 6428: I need help with these problems can you solve these out for me in steps?
Set 5
1. factor completely: x to the 2nd power -7x -30
2. factor completely: x to the 2nd power + 4x -16
3. factor completely: 2x to the 2nd power -11x+5
4. factor completely: 4x to the 2nd power +20x-24
5. factor completely: 4m to the 2nd power - 9
6. factor completely: 16a to the 2nd power - 25b to the 2nd power
7. solve by factoring: x to the 2nd power -x-12=0
8. solve by factoring: 2c to the 2nd power -5=-9c
9. solve the equation:(x+6)(x-7)(x-8)(x+9)=0
10. find the dimensions of the rectangle if the width is 3 feet less than the length and the area is 40ft to the 2nd power

Answer by ichudov(507)   (Show Source): You can put this solution on YOUR website!
I'll do a couple for you....
Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: x=-6,x=7,x=8,x=-9.
  • Graphical form: Equation was fully solved.
  • Text form: (x+6)*(x-7)*(x-8)*(x+9)=0 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( (x+6)*(x-7)*(x-8)*(x+9)=0 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION


Look at .
Notes known roots (x-(-6))

Look at .
Remove unneeded parentheses around factor highlight_red%28+1+%29
It becomes .

Look at .
Remove extraneous '1' from product highlight_red%28+1+%29
It becomes .

Look at .
Notes known roots (x-(7))

Look at .
Remove unneeded parentheses around factor highlight_red%28+1+%29
It becomes .

Look at .
Remove extraneous '1' from product highlight_red%28+1+%29
It becomes .

Look at .
Notes known roots (x-(8))

Look at .
Remove unneeded parentheses around factor highlight_red%28+1+%29
It becomes .

Look at .
Remove extraneous '1' from product highlight_red%28+1+%29
It becomes .

Look at .
Remove unneeded parentheses around terms highlight_red%28+x+%29,highlight_red%28+9+%29
It becomes .

Look at .
Solved linear equation highlight_red%28+x%2B9=0+%29 equivalent to x+9 =0
It becomes .
Result:
This is an equation! Solutions: x=-6,x=7,x=8,x=-9.

Universal Simplifier and Solver


Done!

Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=81 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 5, 0.5. Here's your graph:

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