SOLUTION: Three numbers are so related that the second number is 2 more than the first number and third number is 4 more than the first. Find the numbers if the sum of their squares is 56 mo

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Three numbers are so related that the second number is 2 more than the first number and third number is 4 more than the first. Find the numbers if the sum of their squares is 56 mo      Log On


   

Question 640306: Three numbers are so related that the second number is 2 more than the first number and third number is 4 more than the first. Find the numbers if the sum of their squares is 56 more than three times the square of the smallest number.
Answer by sachi(548) About Me  (Show Source):
You can put this solution on YOUR website!
let the 1st no =x
2nd no =x+2
& 3rd no =x+4
the sum of their squares is 56 more than three times the square of the smallest number.
so x^2+(x+2)^2+(x+4)^2=56+3*x^2
or x^2+x^2+4x+4+x^2+8x+16=56+3x^2
or3x^2+12x+20=56+3x^2
or 12x=56-20=36
or x=36/12=3
so the nos are 3,5,7 ans