# SOLUTION: Select any two integers between -12 and +12 which will become solutions to a system of two equations. Write two equations that have your two integers as solutions. Show how you b

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: Select any two integers between -12 and +12 which will become solutions to a system of two equations. Write two equations that have your two integers as solutions. Show how you b      Log On

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 Question 636519: Select any two integers between -12 and +12 which will become solutions to a system of two equations. Write two equations that have your two integers as solutions. Show how you built the equations using your integers. Your solution and equations should not be the same as those of other students or the textbook. There are infinite possibilities. Solve your system of equations by the addition/subtraction method. Make sure you show the necessary 5 steps. Use the example on page 426 of Mathematics in Our World as a guide. Answer by ankor@dixie-net.com(15746)   (Show Source): You can put this solution on YOUR website! Select any two integers between -12 and +12 which will become solutions to a system of two equations. : Choose two integers, x =-5 and y=+10 : 1st equation 3(-5) + 2(10) = -15 + 20 = 5 3x + 2y = 5 : 2nd equation 6(-5) - 4(10) = -30 - 40 = -70 6x - 4y = -70 : Our two equations 3x + 2y = 5 6x - 4y = -70 : Solve this using the addition method Multiply the 1st equation by 2, add to the 2nd equation 6x + 4y = 10 6x - 4y = -70 ----------------adding eliminates y, find x 12x + 0 = -60 12x = -60 x = -60/12 x = -5 : Find y using the 1st equation, replace x with -5 3(-5) + 2y = 5 -15 + 2y = 5 2y = 5 + 15 2y = 20 y = 20/2 y = 10 : You can check the solution again in the 2nd equation